Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|

Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |

Language: Joke with Turtles
Description There is a famous joke-riddle for children:
Three turtles are crawling along a road. One turtle says: "There are two turtles ahead of me." Now in this problem you have n turtles crawling along a road. Some of them are crawling in a group, so that they do not see members of their group neither ahead nor behind them. Each turtle makes a statement of the form: "There are ai turtles crawling ahead of me and bi turtles crawling behind me." Your task is to find the minimal number of turtles that must be lying. Let us formalize this task. Turtle i has xi coordinate. Some turtles may have the same coordinate. Turtle i tells the truth if and only if ai is the number of turtles such that xj > xi and bi is the number of turtles such that xj < xi. Otherwise, turtle i is lying. Input The first line of the input contains integer number n (1 <= n <= 1000). It is followed by n lines containing numbers ai and bi (0 <= ai, bi <= 1000) that describe statements of each turtle for i from 1 to n. Output On the first line of the output file write an integer number m -- the minimal number of turtles that must be lying, followed by m integers -- turtles that are lying. Turtles can be printed in any order. If there are different sets of m lying turtles, then print any of them. Sample Input 5 0 2 0 3 2 1 1 2 4 0 Sample Output 2 1 4 Source |

[Submit] [Go Back] [Status] [Discuss]

All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di

Any problem, Please Contact Administrator