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很简答的啊！不过有个地方要提醒一下后人！/* 这是个简单的计算几何题目 复杂度为O(n*m) 只要求出原点与星星的直线同原点与望眼镜的直线构成的夹角 小于给定的W就认为是可以看的到的，但是要注意被重复看的 星星应该用一个use[M]来标记他，看到就标为1，否则为0 最后统计use[M]中1的个数即为看的星星的个数! */ Followed by:
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