//Problem 1006
import java.io.*;
import java.util.*;

public class Main {
	
	public static void main(String[] args) throws IOException {
		int pT = 23, eT = 28, iT = 33;
		int eiT = 28 * 33;
		int caseNum = 1;
		BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer(stdin.readLine());
		int p = Integer.parseInt(st.nextToken());
		int e = Integer.parseInt(st.nextToken());
		int i = Integer.parseInt(st.nextToken());
		int d = Integer.parseInt(st.nextToken());
		while(p!=-1 && e!=-1 && i!=-1 && d!=-1) {
			if(p==0 || e==0 || i==0) {
				System.out.println("Case " + (caseNum++) + ": the next triple peak occurs in " + (21252-d) + " days.");
			}else {
				int delta;
				if(i!=e) {
					delta = i - e;
					for(; delta%eT!=0 || delta<0; delta+=iT);	//寻找e与i高峰同时出现的日期距给定e的日数
				}else delta = 0;
				if(delta+e!=p) {
					delta += e - p;
					for(; delta%pT!=0 || delta<0; delta+=eiT);	//寻找三峰同时出现的日期距给定p的日数
				}
				int nextTriPeak = p + delta - d;	//此处找到的三峰日数是给定的p,e,i往后的日数
				if(nextTriPeak<=0) nextTriPeak += 21252;	//若三峰出现在d之前(含d当日)、p,e,i之后，则要加上21252
				else if(nextTriPeak>21252) nextTriPeak -= 21252;	//若三峰出现在d之后、p,e,i之前，则要减去21252
				System.out.println("Case " + (caseNum++) + ": the next triple peak occurs in " + nextTriPeak + " days.");
			}
			st = new StringTokenizer(stdin.readLine());
			p = Integer.parseInt(st.nextToken());
			e = Integer.parseInt(st.nextToken());
			i = Integer.parseInt(st.nextToken());
			d = Integer.parseInt(st.nextToken());
		}
	}
}