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Re:50题纪念

Posted by linlw at 2008-08-11 16:42:00 on Problem 3278
In Reply To:50题纪念 Posted by:rudylau at 2008-07-30 13:26:16
> #include<iostream>
> using namespace std;
> int a[200000],b[100000],c[100000];
> unsigned R,co,N,K,i,j;
> void Rudy(int l)
> {
> 	co++;i=0;
> 	if(co%2)
> 	for(j=1;j<=l;j++)
> 	{
> 		if(!a[2*b[j]]&&b[j]<=50002){a[2*b[j]]=1;c[++i]=2*b[j];}
> 		if(!a[b[j]-1]&&b[j]>=2){a[b[j]-1]=1;c[++i]=b[j]-1;}
> 		if(!a[b[j]+1]&&b[j]<=100002){a[b[j]+1]=1;c[++i]=b[j]+1;}
> 	}
> 	else
> 	for(j=1;j<=l;j++)
> 	{
> 		if(!a[2*c[j]]&&c[j]<=50002){a[2*c[j]]=1;b[++i]=2*c[j];}
> 		if(!a[c[j]-1]&&c[j]>=2){a[c[j]-1]=1;b[++i]=c[j]-1;}
> 		if(!a[c[j]+1]&&c[j]<=100002){a[c[j]+1]=1;b[++i]=c[j]+1;}
> 	}
> 	if(a[K]){cout<<co<<endl;return;}
> 	Rudy(i);
> }
> int main()
> {	
> 	cin>>N>>K;
> 	if(N>=K)cout<<N-K<<endl;
> 	else{b[1]=N;Rudy(1);}
> 	return 0;
> }
同祭

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