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原来是搞错了这题的逻辑我就觉得照搬2492的程序怎么还会出错 原来我认为是两个人有一个任何以没有对立的人时 输出not sure,其他的进行判断 原来时两人祖先相等时输出same,和对立相等时输出different 其他输出not sure 逻辑时这样的才对 fa=find_set(a); fb=find_set(b); if(fa==fb) printf("In the same gang.\n"); else if(fa==find_set(opp[fb])) printf("In different gangs.\n"); else printf("Not sure yet.\n"); Followed by:
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