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Re:和你一样崩溃中In Reply To:这题思路不是这样吗?我感觉没错啊.. Posted by:timeloop at 2008-07-27 17:17:51 #include<iostream> using namespace std; #include<fstream> void shaixuan(int & m,int& n,int c,char op,int & x) { if(op=='AND'&&c==1) { if(m==-1&&n==-1) { m=n=1; x=-1; } else if(m==0||n==0) { cout<<"NO"<<endl; exit(0); } }//----------------------------------------------------------- if(op=='OR'&&c==0) { if(m==-1&&n==-1) { m=n=0; x=-1; } else if(m==1||n==1) { cout<<"NO"<<endl; exit(0); } }//---------------------------------------------------------- if(op=='XOR'&&c==0) { if(m==1&&n==0||m==0&&n==1) { cout<<"NO"<<endl; exit(0); } if(m==1&&n==-1) { n=1; x=-1; } else if(m==0&&n==-1) { n=0; x=-1; } else if(m==-1&&n==1) { m=1; x=-1; } else if(m==-1&&n==0) { m=0; x=-1; } } if(op=='XOR'&&c==1) { if(m==1&&n==1||m==0&&n==0) { cout<<"NO"<<endl; } else if(m==1&&n==-1) { n=0; x=-1;} else if(m==0&&n==-1) { n=1;x=-1;} else if(m==-1&&n==1) { m=0; x=-1;} else if(m==-1&&n==0) { m=1;x=-1;} } } struct info { int m; int n; int c; char op; int flag; } ; int main() { ifstream fin("11.in"); struct info edge[10000]; int i; int x[1000]; int n,m; fin>>n>>m; for(i=0;i<m;i++) { fin>>edge[i].m>>edge[i].n>>edge[i].c>>edge[i].op; edge[i].flag =0; shaixuan ( x[edge[i].m] , x[edge[i].n] , edge[i].c ,edge[i].op ,edge[i].flag ); } cout<<"YES"<<endl; return 0; } Followed by:
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