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这题思路不是这样吗?我感觉没错啊..WA了,哪位站友能告诉我错在哪吗?
#include <stdio.h>
#include <string.h>
int a[1000000];
int b[1000000];
int c[1000000];
char d[1000000][4];
bool t[1001][1001][4];/*0表 同时0;1表同时1;2表0,1;3表1,0;*/
int main()
{
/*freopen("in.txt","r",stdin);
freopen("out.txt","w",stdout);*/
int n,m,i,j,k,tag;
while (scanf("%d%d",&n,&m)!=EOF)
{
for(i=0;i<m;i++)
{
scanf("%d %d %d",&a[i],&b[i],&c[i]);
gets(d[i]);
}
if(m==0)
{
printf("YES\n");
continue;
}
tag=0;
memset(t,0,sizeof(t));
for(i=0;i<m;i++)
{
if(d[i][0]=='A')
{
if(c[i]==1)
{
t[a[i]][b[i]][1]=t[b[i]][a[i]][1]=1;
}
else
{
t[a[i]][b[i]][0]=t[b[i]][a[i]][0]=t[a[i]][b[i]][2]=t[a[i]][b[i]][3]
=t[b[i]][a[i]][2]=t[b[i]][a[i]][3]=1;
}
if((t[a[i]][b[i]][0]||t[a[i]][b[i]][2])&&(t[a[i]][b[i]][1]||t[a[i]][b[i]][3]))
{
tag=1;
break;
}
if((t[b[i]][a[i]][0]||t[b[i]][a[i]][2])&&(t[b[i]][a[i]][1]||t[b[i]][a[i]][3]))
{
tag=1;
break;
}
}
else if(d[i][0]=='O')
{
if(c[i]==1)
{
t[a[i]][b[i]][1]=t[a[i]][b[i]][2]=t[a[i]][b[i]][3]=1;
t[b[i]][a[i]][1]=t[b[i]][a[i]][2]=t[b[i]][a[i]][3]=1;
}
else
{
t[a[i]][b[i]][0]=t[b[i]][a[i]][0]=1;
}
if((t[a[i]][b[i]][0]||t[a[i]][b[i]][2])&&(t[a[i]][b[i]][1]||t[a[i]][b[i]][3]))
{
tag=1;
break;
}
if((t[b[i]][a[i]][0]||t[b[i]][a[i]][2])&&(t[b[i]][a[i]][1]||t[b[i]][a[i]][3]))
{
tag=1;
break;
}
}
else if(d[i][0]=='X')
{
if(c[i]==1)
{
t[a[i]][b[i]][2]=t[a[i]][b[i]][3]=1;
t[b[i]][a[i]][2]=t[b[i]][a[i]][3]=1;
}
else
{
t[a[i]][b[i]][1]=t[b[i]][a[i]][1]=t[a[i]][b[i]][0]=t[b[i]][a[i]][0]=1;
}
if((t[a[i]][b[i]][0]||t[a[i]][b[i]][2])&&(t[a[i]][b[i]][1]||t[a[i]][b[i]][3]))
{
tag=1;
break;
}
if((t[b[i]][a[i]][0]||t[b[i]][a[i]][2])&&(t[b[i]][a[i]][1]||t[b[i]][a[i]][3]))
{
tag=1;
break;
}
}
}
if(tag)
printf("NO\n");
else
printf("YES\n");
}
return 0;
}
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