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为何超时?请大牛们指点#include <stdio.h>
#include <math.h>
#include <string.h>
#include <stdlib.h>
#define MV 1030
//////////////////////////////////////////////////////////////////////////
//////////////////////////////////////////////////////////////////////////
//////////////////////////2维树状数组/////////////////////////////////////
//////////////////////////////////////////////////////////////////////////
//////////////////////////////////////////////////////////////////////////
/*
int lowbit(int x)
{
return x&(x^(x-1));
}
*/
inline int lowbit(int x)
{
return x&(-x);
}
inline void add_ta2(int (*A)[MV],int n,int x,int y,int v)
{
int ty;
while(x<=n)
{
ty=y;
while(ty<=n)
{
A[x][ty]+=v;
ty+=lowbit(ty);
}
x+=lowbit(x);
}
}
inline int sum_ta2(int (*A)[MV],int n,int x,int y)
{
int sum,ty;
sum=0;
while(x>0)
{
ty=y;
while(ty>0)
{
sum+=A[x][ty];
ty-=lowbit(ty);
}
x-=lowbit(x);
}
return sum;
}
//////////////////////////////////////////////////////////////////////////
//////////////////////////////////////////////////////////////////////////
int A[MV][MV],n,x,y,x1,y11,v;
int main()
{
int op;
while(true)
{
scanf("%d",&op);
switch(op)
{
case 0:
memset(A,0,sizeof(A));
scanf("%d",&n);
break;
case 1:
scanf("%d %d %d",&x,&y,&v);
add_ta2(A,n,x,y,v);
break;
case 2:
scanf("%d %d %d %d",&x,&y,&x1,&y11);
printf("%d\n",sum_ta2(A,n,x1,y11)-sum_ta2(A,n,x-1,y11)-sum_ta2(A,n,x1,y-1)+sum_ta2(A,n,x-1,y-1));
break;
case 3:
return 0;
}
}
return 0;
}
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