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Re:ACLAIn Reply To:ACLA Posted by:jxwking2010 at 2006-07-20 17:10:27 for(j=0;j<i;j++) { if(a[j]>=65&&a[j]<=69) {a[j]=a[j]+21;continue;} if(a[j]>69&&a[j]<=90) a[j]=a[j]-5; } 改成 for(j=0;j<strlen(a);j++) { if(a[j]>=65&&a[j]<=90) a[j]=(a[j]+21-65)%26+65; }好看 Followed by: Post your reply here: |
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