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Re:ACLAIn Reply To:ACLA Posted by:jxwking2010 at 2006-07-20 17:10:27 for(j=0;j<i;j++)
{
if(a[j]>=65&&a[j]<=69)
{a[j]=a[j]+21;continue;}
if(a[j]>69&&a[j]<=90)
a[j]=a[j]-5;
}
改成
for(j=0;j<strlen(a);j++)
{
if(a[j]>=65&&a[j]<=90)
a[j]=(a[j]+21-65)%26+65;
}好看
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