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大牛，我不懂您的公式，我是分奇偶性讨论的，也是sqrt(n)的算法。16MS AC.In Reply To:说说两个简单公式. Posted by:KosonLau at 2007-04-28 21:22:36 > k=(sqrt(1+8*n)-1)/2,即子序列的长度不会超过k. 接着从1到k一个一个判断 a=(2*n-k*k+k)%(2*k)是否为0,如果是则总数加1,否则继续循环. > > Followed by: Post your reply here: |
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