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Re:在VC6.0上能运行,结果一样,但是狂RE,各位大虾帮忙看看,我才大一,新手,想了很久了

Posted by E10714147 at 2008-07-16 16:49:39 on Problem 1002
In Reply To:在VC6.0上能运行,结果一样,但是狂RE,各位大虾帮忙看看,我才大一,新手,想了很久了 Posted by:317781250 at 2008-07-13 23:24:49
> #include "stdio.h"
> #include "string.h"
> 
> main()
> {int n,x[100]={1},y=0,i,j,t,r,z[100]={0};
> char a[100][100],b[100][8],s[100];
>  scanf("%d",&n);
>  for(i=0;i<n;i++)
>   scanf("%s",&a[i]);
> 
> 
> 
> 
>  for(i=0;i<n;i++)                                     /*将'-'去掉,搞成一连没有间隔的字符*/ 
>    for(j=0;a[i][j]!='\0';j++)
>    {if(a[i][j]=='-'&&a[i][j+1]=='-')
>    {for(t=j;(a[i][t+2])!='\0';t++) a[i][t]=a[i][t+2];}
>      if(a[i][j]=='-')
>      	{for(t=j;(a[i][t+1])!='\0';t++)
>      	  a[i][t]=a[i][t+1];
>      	}
>    }
>    for(i=0;i<n;i++){a[i][7]='\0';}                    /*在最后加上结束符*/
> 
>  for(i=0;i<n;i++)
>   {for(j=0;j<8;j++)
>   	{
>   	 if(a[i][j]=='A'||a[i][j]=='B'||a[i][j]=='C')
>   	  b[i][j]='2';
>   	 else if(a[i][j]=='D'||a[i][j]=='E'||a[i][j]=='F')
>             b[i][j]='3';
>           else if(a[i][j]=='G'||a[i][j]=='H'||a[i][j]=='I')
>                 b[i][j]='4';
>                else if(a[i][j]=='J'||a[i][j]=='K'||a[i][j]=='L')
>                       b[i][j]='5';
>                      else if(a[i][j]=='M'||a[i][j]=='N'||a[i][j]=='O')
>                             b[i][j]='6';
>                            else if(a[i][j]=='P'||a[i][j]=='R'||a[i][j]=='S')
>                                   b[i][j]='7';
>                                  else if(a[i][j]=='T'||a[i][j]=='U'||a[i][j]=='V')
>                                        b[i][j]='8';
>                                         else if(a[i][j]=='W'||a[i][j]=='X'||a[i][j]=='Y')
>                                                b[i][j]='9';
>                                                else b[i][j]=a[i][j];
>   }}
> 
>  
>  for(i=0;i<n-1;i++)               /*排序*/
>   for(j=i+1;j<n;j++)
>     {if(b[i][0]>b[j][0])
>       {strcpy(s,b[i]);
>        strcpy(b[i],b[j]);	
>        strcpy(b[j],s);}}
> for(i=1;i<n;i++)                  /*如果某一行是前面出现过的,则z[i]=1*/
> for(t=0;t<i;t++)
> 	if(strcmp(b[t],b[i])==0)
> 	 {z[i]=1;}
> 
> for(i=0;i<n;i++)	               /*如果某一行,这一行的z[i]=0,即前面没出现过,就计算它后面有多少个一样的*/
> 	if(z[i]==0)                   
> 	 {for(j=i+1;j<n;j++)
> 	 	{if(strcmp(b[i],b[j])==0)
> 	 	 x[i]++;}
>      }
> for(i=1;i<n;i++) x[i]++;
> 	 for(t=0;t<n;t++)
> 	 {if(x[t]>1)
> 	 {printf("%c%c%c-%c%c%c%c %d\n",b[t][0],b[t][1],b[t][2],b[t][3],b[t][4],b[t][5],b[t][6],x[t]);
>     	y=1;}}
>  
>       if(y!=1)
>      printf("No duplicates.\n");
>    }

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