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碰到熟人了~In Reply To:奇数:f[n]=f[n-1];偶数:f[n]=f[n-2]+f[(n-2)/2]+f[(n-4)/4]+....f[(n-t)/t]:其中(n-t)%t==0 Posted by:yxysdcl at 2008-03-03 23:06:20 Followed by: Post your reply here: |
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