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Re:那位大牛能解释这个问题，俩个非常相似的程序，一个ac（0ms），一个tle！！！In Reply To:那位大牛能解释这个问题，俩个非常相似的程序，一个ac（0ms），一个tle！！！ Posted by:2004huangyimin at 2006-04-25 14:08:21 > Source
>
> Problem Id:1942 User Id:2004huangyimin
> Memory:48K Time:1015MS
> Language:C++ Result:Time Limit Exceed
>
> Source
>
> #include < iostream >
> using namespace std;
> unsigned int com (unsigned int n,unsigned int m)
> {
> double i;
> double result(1);
> if ( n >= m - n ){ n = m-n; }
> for ( i = m;i >= m-n+1;i-=1 )
> {
> result *= (i / (i - (m - n)));
> }
> return result;
> }
> int main()
> {
> unsigned int n,m;
> while (1)
> {
> scanf("%d%d",&n,&m);
> if ( n==0 && m==0 ){ break; }
> printf("%d\n",com (n,m+n));
> }
> return 0;
> }
>
> Source
>
> Problem Id:1942 User Id:2004huangyimin
> Memory:56K Time:0MS
> Language:C++ Result:Accepted
>
> Source
>
> #include < iostream >
> using namespace std;
> double com (double n,double m)
> {
> double i;
> double result(1);
> if ( n >= m - n ){ n = m-n; }
> for ( i = m;i >= m-n+1;i-=1 )
> {
> result *= (i / (i - (m - n)));
> }
> return result;
> }
> int main()
> {
> double n,m;
> while (1)
> {
> scanf("%lf%lf",&n,&m);
> if ( n==0 && m==0 ){ break; }
> printf("%.0lf\n",com (n,m+n));
> }
> return 0;
> }
>
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