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Re:f(n, h) = (H[i]-h)^2 + min { -Ch+low(n-1, h), Ch+high(n-1, h) }

Posted by gzw_02 at 2008-07-04 17:19:44 on Problem 3612
In Reply To:f(n, h) = (H[i]-h)^2 + min { -C*h+low(n-1, h), C*h+high(n-1, h) } Posted by:Vi_King at 2008-07-04 11:39:05

> f(n, h) = (H[i]-h)^2 + min { -C*h+low(n-1, h), C*h+high(n-1, h) }
> f(n, h) = (H[i]-h)^2 + min { -C*h+low(n-1, h), C*h+high(n-1, h) }

Hi, could you provide further details of your Dp formula?
I can't guess the meanings.
I'm not sure what does f(n,h) mean, especailly h.
why need to add '-' in front of C*h when it is 'low' ?  
And what's the difference between low(n-1,h) and high(n-1,h)?

Followed by:

Re:f(n, h) = (H[i]-h)^2 + min { -C*h+low(n-1, h), C*h+high(n-1, h) } (90) linmeng 2009-07-28 15:32:22

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Re:f(n, h) = (H[i]-h)^2 + min { -C*h+low(n-1, h), C*h+high(n-1, h) }

Re:f(n, h) = (H[i]-h)^2 + min { -Ch+low(n-1, h), Ch+high(n-1, h) }