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Re:不知道这个算法行不行

Posted by gzw_02 at 2008-06-26 14:52:52 on Problem 1183
In Reply To:不知道这个算法行不行 Posted by:Shinjikun at 2006-02-08 01:49:13 
我的想法和你类似，“b的取值应在a+(a^2+1)^(1/2)周围
”，
 但是似乎没有考虑到最值可能位于2/(a^2+1)^(1/2)的右边的情况。
我也不明白为什么只穷举2/(a^2+1)^(1/2)的左半部分就可以AC，奇怪。。
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