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POJ2542 胜者树做的,WA了,哪位大牛帮忙看看?#include <stdio.h> #define MAXVALUE 1000000 typedef struct{ int min, max; }TREE; TREE tree[1000000]; int A[50010]; int min(int a, int b) {return ((a < b) ? a : b);} int max(int a, int b) {return ((a > b) ? a : b);} /* [l, r] : 当前结点代表的区域 node : 当前结点编号 建树复杂度为O(N) 初始调用Build_Tree(1, N, 1); */ void Build_Tree(int l, int r, int node){ if(l == r) { tree[node].min = A[l]; tree[node].max = -1; return; } int k = (l + r) / 2; Build_Tree(l, k, node*2); Build_Tree(k + 1, r, node*2+1); tree[node].min = min (tree[node*2].min, tree[node*2+1].min); tree[node].max = max (tree[node*2].max, tree[node*2+1].max); return; } int GetMin(int l, int r, int value, int node){ if(node == 1 && tree[node].min > value) return -1; else if(l == r){ if(tree[node].min < value) return l; else return -1; } else{ if(tree[node*2].min < value) return GetMin(l, (l+r)/2, value, node*2); else return GetMin((l+r)/2+1, r, value, node*2+1); } } int GetMax(int l, int r, int i, int j, int node){ if(l == r) return l; int k = (l + r) / 2; if(j <= k) return GetMax(l, k, i, j, node*2); else if(i > k) return GetMax(k+1, r, i, j, node*2+1); else if(tree[node*2].max >= tree[node*2+1].max) { if(j <= k) return GetMax(l, k, i, j, node*2); else return GetMax(l, k, i, k, node*2); } else{ if(i > k) return GetMax(k+1, r, i, j, node*2+1); else return GetMax(k+1, r, k+1, j, node*2+1); } } void Insert(int l, int r, int k, int value, int node){ if(l == r){ tree[node].max = value; tree[node].min = value; return; } if(k > (l + r) / 2 ) Insert((l + r) / 2 + 1, r, k, value, node*2+1); else Insert(l, (l+r)/2, k, value, node*2); tree[node].min = min (tree[node*2].min, tree[node*2+1].min); tree[node].max = max (tree[node*2].max, tree[node*2+1].max); return; } int main() { int i, n, fir, Min, ans, sec, ANS; while(scanf("%d", &n) != EOF){ for(i = 1; i <= n; i++) A[i] = MAXVALUE; ANS = -1; Build_Tree(1, n, 1); for(i = 1; i <= n; i++) scanf("%d", A+i); for(i = n; i >= 1; i--){ fir = i; Min = GetMin(1, n, A[i], 1); if(Min == -1) sec = n; else sec = Min-1; ans = GetMax(1, n, fir, sec, 1) - fir; //printf("i = %d, A[i] = %d, Min = %d, fir = %d, sec = %d, ans = %d\n", i, A[i], Min, fir, sec, ans); if(ans > ANS) ANS = ans; Insert(1, n, i, A[i], 1); } if(ANS > 0) printf("%d\n", ANS); else printf("-1\n"); } return 0; } Followed by:
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