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Re:迭代即可In Reply To:迭代即可 Posted by:hf8171038 at 2007-08-02 12:08:29 > if(k%2==1) > F=((d*f2+e*f1-f*f0)%g+g)%g; > else > F=((f*f2-d*f1+e*f0)%h+h)%h; > f0=f1;f1=f2;f2=F; 感谢提示!! Followed by: Post your reply here: |
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