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能通过,waIn Reply To:你能通过这些数据吗? Posted by:zhaokkk27 at 2007-09-10 18:05:34 #include<stdio.h>
#include<string.h>
int n,i,j,k,t;
char c;
int w[1001]={0},la[101]={0},vi[1001]={0},q=0;
int bz[101][550]={0},by[101][550]={0},bal[101]={0},ans,right,left;
int main()
{
scanf("%d %d",&t,&n);
for(j=1;j<n+1;j++)
{
scanf("%d",&la[j]);
for(i=0;i<la[j];i++)
{scanf("%d",&bz[j][i]);
//vi[bz[j][i]]=1;
}
for(i=0;i<la[j];i++)
{scanf("%d",&by[j][i]);
//vi[bz[j][i]]=1;
}
scanf("%c",&c);
scanf("%c",&c);
if(c=='=')
bal[j]=0;
else {//q=1;
//f/or(i=0;i<la[j];i++)
//vi[bz[j][i]]=1,vi[by[j][i]]=1;
if(c=='<')
bal[j]=-1;
else bal[j]=1;
}
//printf("%d\n",bal[j]);
}
for(i=1;i<=t;i++)
w[i]=1;
ans=-1;
for(i=1;i<=t;i++)
{
//if(vi[i]==0&&q==1)
// continue;
w[i]=0;
for(j=1;j<n+1;j++)
{
right=left=0;
for(k=0;k<la[j];k++)
{
left=w[bz[j][k]]+left;
right=w[by[j][k]]+right;
}
if(left<right&&bal[j]!=-1)
break;
if(left>right&&bal[j]!=1)
break;
if(left==right&&bal[j]!=0)
break;
}
if(ans!=-1&&j==n+1)
{ans=-1;break;}
if(j==n+1)
ans=i;
if(ans==-1)
{
w[i]=2;
for(j=1;j<n+1;j++)
{
right=left=0;
for(k=0;k<la[j];k++)
{
left=w[bz[j][k]]+left;
right=w[by[j][k]]+right;
}
if(left<right&&bal[j]!=-1)
break;
if(left>right&&bal[j]!=1)
break;
if(left==right&&bal[j]!=0)
break;
}
if(ans!=-1&&j==n+1)
{ans=-1;break;}
if(j==n+1)
ans=i;
}
w[i]=1;
}
if(ans!=-1)
printf("%d\n",ans);
else
printf("0\n");
scanf("%d");
return 0;
}
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