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Re:这题怎么做啊，大手给点思路啊.In Reply To:这题怎么做啊，大手给点思路啊. Posted by:ufo008ahw at 2007-11-15 17:54:14 因为有一个最小的c是其他的倍数 我们把所有都/c 这样任意a:b都可以看成a:1和1:b的齿轮连起来 我们只要bfs出1-10000中所有1:x即可 然后分别判断a和b是否可达，都是就YES Followed by:
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