#include<iostream>
using namespace std;
int main()
{
    long sum;
	int t,n;
	cin>>t;
	int k=1;
	while(t--)
	{
		cin>>n;
    	sum=n*(n+1)*(n+2)*(n+3)/8;
		cout<<k++<<" "<<n<<" "<<sum<<endl;
	}
	return 0;
}

• Re:求助！！！sos（why wa！）【附代码】 (372) ecjtuQX 2008-08-27 20:09:30
• n*(n+1)*(n+2)*(n+3)最大值大于2^32,应该用long long (0) oassuperhan 2009-01-21 22:11:32