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不用二分,对原来的多边形的每一条边都往里缩r的距离,得到一个新的多边形,在这个多边形上找两个最远的点对就可以了

Posted by 20053565 at 2008-05-05 17:09:35 on Problem 3384
In Reply To:请教各位大牛,说这个题,最好的状况,当然是两个圆都分开,最差的是两个圆重合,那如果要是二分猜测答案,新组成的这个胶囊型的图,如何迅速的判断它是否可以被容纳在这个多边形里呢? Posted by:MetalHeart at 2008-05-05 16:28:51


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