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我 n*n*n OLE,想到一个 n*n*2 做法就AC了In Reply To:why OLE? for the tailing new line??? Posted by:qiqilrq at 2008-04-04 11:31:13 >
> char unb[50][50][50];
> int n;
>
> char get_ch(int x)
> {
> if(x<26) return x+'a';
> x-=26; return x+'A';
> }
>
> int main(){
> scanf("%d",&n);
>
> int i,j,k;
> for(i=0;i<n;i++)
> memset(unb[i], get_ch(i), sizeof(unb[0]));
> for(i=0;i<n;i++){
> char ch=get_ch(i);
> for(k=0;k<n;k++)
> unb[k][i][i]=ch;
> }
> printf("%d 50 50\n",n);
> for(i=0;i<n;i++){
> for(j=0;j<50;j++, puts("")){
> for(k=0;k<50;k++)
> putchar(unb[i][j][k]);
> }
> puts("");
> }
> }
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