#include<stdio.h>
#include<stdlib.h> 
long int tpeak(int p,int e,int i,int d0) 
{
     p=p%23;   
     e=e%28;
     i=i%33;
     long int d=d0;
     d++;
    while(((d-p)%23!=0 || (d-e)%28!=0 || (d-i)%33!=0) && d-d0<21252 )  
    {
      d++;            
    }
  return   d-d0;
}
int main()
{
   int p[100],e[100],l[100],d[100]; 
   int sum,i=0;
   scanf("%d %d %d %d",&p[i],&e[i],&l[i],&d[i]); 
   while(p[i]!=-1)
   {
        i++;
        scanf("%d %d %d %d",&p[i],&e[i],&l[i],&d[i]);            
   }
   sum=i;
   for(i=0;i<sum;i++)
    printf("Case %d: the next triple peak occurs in %ld days.\n",i+1,tpeak(p[i],e[i],l[i],d[i]));
    return 0;
    
    
}

• Re:不可能不对呀？WA 有高手吗 (405) tszcgf 2008-07-22 21:47:48