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memset比循环快，这种情况可能是你的数组开的很大，对于每组case，memset要全部清空，而循环只需要清0 to m+1，case数很多时memset就超时了

Posted by xiaomi at 2004-11-05 00:42:02 on Problem 1974
In Reply To:奇怪ing!!!! Posted by:windbells at 2004-11-04 16:49:03

> 这样写memset(num[i%2],0,sizeof(num[i%2]));超时
> 
> 改为这样就AC了
> for(j=0;j<=m+1;j++)
> 　　num[i%2][j][0]=num[i%2][j][1]=0;
> why???????
>

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