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Re:其实此题是可以用线性规划求解的

Posted by seanwu at 2008-03-28 14:15:11 on Problem 1000
In Reply To:其实此题是可以用线性规划求解的 Posted by:wywcgs at 2008-03-28 14:08:52 
> 设立约束方程：
> x1 >= a
> x1 <= a
> x2 >= b
> x2 <= b
> 之后只需要求目标函数f = x1+x2的最小值即可

不用，应该只需要x1>=a,x2>=b，求目标函数f=x1+x2的最小值即可
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