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Re:我的思路In Reply To:我的思路 Posted by:cactuslrd at 2007-12-26 20:42:38 > 看看x和y谁距离根节点尽，若x比较近，则 > ：（1）先判断x是否为y的祖先； > （2）否则令x=x的祖先； > （3）反复(1)(2)过程 > 大家看一下吧，是这样么，我是用一维数组装的父亲节点，一次AC Followed by: Post your reply here: |
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