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我的思路看看x和y谁距离根节点尽，若x比较近，则 ：（1）先判断x是否为y的祖先； （2）否则令x=x的祖先； （3）反复 大家看一下吧，是这样么，我是用一维数组装的父亲节点，一次AC Followed by: Post your reply here: |
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