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Re:一个通过的思路In Reply To:Re:一个通过的思路 Posted by:cpp0600548268 at 2006-02-28 11:43:32 > 我用的也是这个思路 为什么不对呢? > #include<iostream> > #include<cmath> > using namespace std; > > const int NumOfDollar = 12; > > void main() > { > int num; > char left[3][7] = {'\0'}, right[3][7] = {'\0'}, result[3][5] = {'\0'}; > static int dollar[NumOfDollar], rdollar[NumOfDollar]; > int i, k, j; > char c; > > cin>>num; > > for(k = 0; k < num; k++){ > for(j = 0; j < 3; j++) > cin>>left[j]>>right[j]>>result[j]; > > for(i = 0; i < 3; i++){ > c = result[i][0]; > switch(c){ > case 'u': for(j = 0; left[i][j] != '\0'; j++){ > dollar[left[i][j] - 'A']++; > dollar[right[i][j] - 'A']--; > } > break; > case 'd': for(j = 0; left[i][j] != '\0'; j++){ > dollar[left[i][j] - 'A']--; > dollar[right[i][j] - 'A']++; > } > break; > case 'e': for(j = 0; left[i][j] != '\0'; j++){ > rdollar[left[i][j] - 'A'] = 1; > rdollar[right[i][j] - 'A'] = 1; > } > break; > } > } > > int index; > for(i = 0; rdollar[i] == 1; i++); index = i; > for(; i < NumOfDollar; i++){ > if(rdollar[i] == 0){ > if(abs(dollar[i]) > abs(dollar[index])) index = i; > } > } > if(dollar[index] > 0) cout<<(char)('A' + index)<<" is the counterfeit coin and it is heavy."<<endl; > else cout<<(char)('A' + index)<<" is the counterfeit coin and it is light."<<endl; > } > } Followed by:
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