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Re:ei

Posted by tkchenhetian at 2007-12-10 00:04:36 on Problem 2084 and last updated at 2007-12-10 00:09:06
In Reply To:Re:ei Posted by:happyending at 2006-12-01 20:38:47 
n[k]={n[i]*n[k-1-i]*2(i!=k-1-i)+...+n[i]*n[k-1-i](i=k-1-i),
    for i>=0&&i<=(k-1)/2}  really?
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