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这题枚举就过了。。。 while(p!=-1 && e!=-1 && i!=-1 && d!=-1)
{
p0=p%23;
e0=e%28;
i0=i%33;
count++;
for(day=d+1;(day-p0)%23!=0 || (day-e0)%28!=0 || (day-i0)%33!=0;day++);
printf("Case %d: the next triple peak occurs in %d days.\n", count, day-d);
}
过了,还370MS,数据太弱了~
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