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取最值n - 1次?怎讲？In Reply To:Re:Xn-1 = p * 1 / (1 + (p-a)^b) + Xn * (p-a)^b / (1 + (p-a)^b) 使这个式子取最值迭代n - 1次就可以了 Posted by:TheBeet at 2007-11-13 17:56:27 Followed by: Post your reply here: |
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