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Re:Xn-1 = p * 1 / (1 + (p-a)^b) + Xn * (p-a)^b / (1 + (p-a)^b) 使这个式子取最值迭代n - 1次就可以了In Reply To:北京赛区的J题怎么搞呀??????? Posted by:sohu at 2007-11-13 13:47:08 Followed by:
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