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大家看看我的代码吧!总是WA.小弟在此谢过各位大牛了!#include <iostream.h>
#include <string.h>
#include <stdio.h>
int abc[110000];
int letter(char x)
{
if(x>=48&&x<=57) return x-48;
else if(x<81) return (x-65)/3+2;
else return (x-66)/3+2;
}//将输入的电话号码变成数字码
int paixu(int *a,int n)
{
if(n<=1) return 0;
int low=0,high=n-1;
int key=(a[low]+a[high]+a[(low+high)/2])/3;
int t;
while(low<high)
{
for(;a[high]>=key&&low<high;high--)
;
t=a[low];
a[low]=a[high];
a[high]=t;
for(;a[low]<=key&&low<high;low++)
;
t=a[high];
a[high]=a[low];
a[low]=t;
}
paixu(a,high+1);
paixu(a+high+1,n-high-1);
return 0;
}//快速排序函数
int main()
{
int i,n;
scanf("%d",&n);
char b[100];
if(n==0) return 0;
for(i=0;i<n;i++)
{
int c=0;
scanf("%s",b);
int j,k=1000000;
for(j=0;j<strlen(b);j++)
{
if(b[j]!='-')
{
c+=letter(b[j])*k;
k/=10;
}
}
abc[i]=c;
}
//对电话号码处理后储存在c中,然后转存到数组abc中。
paixu(abc,n);//对abc数组进行排序
int j=1,k=0;
for(i=1;i<n;i++)
{
if(abc[i]==abc[i-1])
j++;
else if(j>1)
{
k=1;
printf("%03d-%04d %d\n",abc[i-1]/10000,abc[i-1]%10000,j);
j=1;
}//输出
}
if(j>1)
{
k=1;
printf("%03d-%04d %d\n",abc[i-1]/10000,abc[i-1]%10000,j);
}//如果最后两个字符相同,将不会输出,所以要补上这句。
if(k==0) printf("No duplicates.\n"); //无符合条件的处理
return 0;
}
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