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这种猪头算法也能AC,这题太水了long int root(long int x,int n) { long int d=x; long int r=1; for(long int i=2;power(i,n)<=x+d;i++) if(abs(power(i,n)-x)<d) { r=i; d=abs(power(i,n)-x); } return r; } Followed by: Post your reply here: |
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