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求解该题要注意的地方

Posted by felips at 2007-10-16 22:41:12 on Problem 1026
输入:
scanf("%d",k);
getchar();
gets(s);
for(i=0;i<=n;i++)
{
    if(s[i]==10 || s[i]==0) s[i]=' ';
}
处理置换群:
分解成循环,对每个循环,做(k mod (循环的阶数))次置换就可得到加密后的信息,不能求所有循环阶数的最小公因子total,然后做total次置换,这样会超时


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