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Wrong answer,请高手指点!//1006.cpp #include <iostream.h> #include <math.h> #include <fstream.h> void main(void){ int p,e,i,d,init; // ifstream fin; // fin.open("in.txt"); cin>>p>>e>>i>>d; for(int x=1;p != -1 ;x++){ if(d >= i){ init = d-(d-i)%33; } else{ init = d+(i-d)%33; } if(init == d) init += 33; for(int n=init;n<=21252+d;n += 33){ if((n-p)%23 == 0){ if((n-e)%28 == 0){ cout<<"Case "<<x<<": the next triple peak occurs in "<<n-d<<" days."<<endl; break; } } if((n+33) > 21252+d){ cout<<"Case "<<x<<": the next triple peak occurs in "<<n-d<<" days."<<endl; } } cin>>p>>e>>i>>d; } // fin.close(); return; } Followed by: Post your reply here: |
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