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非常感谢In Reply To:Re:怎么做呢 Posted by:hust07p43 at 2007-10-10 09:01:04 > f(n) =a1*f(n-1)+a2*f(n-2)+a3*f(n-3) > f(n-1)= f(n-1) > f(n-2)= f(n-2) > > 然后就有 > > f(n) a1 a2 a3 f(n-1) > f(n-1) = 1 0 0 * f(n-2) > f(n-2) 0 1 0 f(n-3) Followed by: Post your reply here: |
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