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Re:多谢

Posted by Methane at 2007-10-10 09:41:14 on Problem 2440
In Reply To:Re:怎么做呢 Posted by:hust07p43 at 2007-10-10 09:01:04 
> f(n)  =a1*f(n-1)+a2*f(n-2)+a3*f(n-3)
> f(n-1)=   f(n-1)
> f(n-2)=             f(n-2)
> 
> 然后就有
> 
> f(n)         a1   a2   a3     f(n-1)
> f(n-1)  =     1    0    0  *  f(n-2)
> f(n-2)        0    1    0     f(n-3)
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