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直接枚举都能过In Reply To:救命啊~~~~~~~~~一直是WA!!! Posted by:trueshlqsh at 2007-10-02 14:36:45 > 我用的DFS,觉得没有问题啊..没有TL,老是WA不知道还有什么情况没有考虑到的啊...... > 谢谢了..给数据或者帮我看看程序:)麻烦了,先谢过:) > #include <iostream> > #include <iomanip> > > using namespace std; > > long n,now[11],best[11]; > double ans,now_ans,a[11],b[11],s[11],d; > bool pd[11]; > > void get_ans(long x) > { > long i; > double temp,tempnow; > > // cout<<x<<endl; > if (x==n+1) { > // cout<<now_ans<<endl; > // cout<<ans<<endl; > // system("pause"); > if (now_ans>ans) { > ans=now_ans; > for (i=0;i<=n;i++) best[i]=now[i]; > } > } > else { > for (i=1;i<=n;i++) > if (pd[i]==false) > { > > now[x]=i; > if (d<a[i]) temp=0; else > if (d<b[i]&&a[i]<=d) temp=(d-a[i])/(b[i]-a[i]); > else temp=1; > tempnow=now_ans; > now_ans=now_ans*temp; > // cout<<x<<":"<<i<<endl; > // cout<<a[i]<<"/"<<d<<"/"<<b[i]<<endl; > // cout<<temp<<"!!"<<now_ans<<endl; > d=d+s[i]; > pd[i]=true; > get_ans(x+1); > pd[i]=false; > d=d-s[i]; > if (now_ans==0) now_ans=tempnow; > else now_ans=now_ans/temp; > now[x]=0; > } > } > } > > int main() > { > long i; > > //init; > cin>>n>>d; > for (i=1;i<=n;i++) cin>>a[i]>>b[i]>>s[i]; > now[0]=0; > for (i=1;i<=n;i++) pd[i]=false; > > //main; > now_ans=1.000;ans=0.000; > get_ans(1); > > //print; > cout<<setiosflags(ios::fixed)<<setprecision(3)<<ans<<endl; > for (i=1;i<=n-1;i++) cout<<best[i]<<" "; > cout<<best[n]<<endl; > system("pause"); > return 0; > } Followed by:
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