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直接枚举都能过In Reply To:救命啊~~~~~~~~~一直是WA!!! Posted by:trueshlqsh at 2007-10-02 14:36:45 > 我用的DFS,觉得没有问题啊..没有TL,老是WA不知道还有什么情况没有考虑到的啊......
> 谢谢了..给数据或者帮我看看程序:)麻烦了,先谢过:)
> #include <iostream>
> #include <iomanip>
>
> using namespace std;
>
> long n,now[11],best[11];
> double ans,now_ans,a[11],b[11],s[11],d;
> bool pd[11];
>
> void get_ans(long x)
> {
> long i;
> double temp,tempnow;
>
> // cout<<x<<endl;
> if (x==n+1) {
> // cout<<now_ans<<endl;
> // cout<<ans<<endl;
> // system("pause");
> if (now_ans>ans) {
> ans=now_ans;
> for (i=0;i<=n;i++) best[i]=now[i];
> }
> }
> else {
> for (i=1;i<=n;i++)
> if (pd[i]==false)
> {
>
> now[x]=i;
> if (d<a[i]) temp=0; else
> if (d<b[i]&&a[i]<=d) temp=(d-a[i])/(b[i]-a[i]);
> else temp=1;
> tempnow=now_ans;
> now_ans=now_ans*temp;
> // cout<<x<<":"<<i<<endl;
> // cout<<a[i]<<"/"<<d<<"/"<<b[i]<<endl;
> // cout<<temp<<"!!"<<now_ans<<endl;
> d=d+s[i];
> pd[i]=true;
> get_ans(x+1);
> pd[i]=false;
> d=d-s[i];
> if (now_ans==0) now_ans=tempnow;
> else now_ans=now_ans/temp;
> now[x]=0;
> }
> }
> }
>
> int main()
> {
> long i;
>
> //init;
> cin>>n>>d;
> for (i=1;i<=n;i++) cin>>a[i]>>b[i]>>s[i];
> now[0]=0;
> for (i=1;i<=n;i++) pd[i]=false;
>
> //main;
> now_ans=1.000;ans=0.000;
> get_ans(1);
>
> //print;
> cout<<setiosflags(ios::fixed)<<setprecision(3)<<ans<<endl;
> for (i=1;i<=n-1;i++) cout<<best[i]<<" ";
> cout<<best[n]<<endl;
> system("pause");
> return 0;
> }
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