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不要想复杂，按照字符串输入之后，就for (i=0;s[i];i++) {n+=s[i]-'0'; if (n>9) n-=9;}就这就搞定了哈。

Posted by bluegenelove at 2007-09-29 23:53:27 on Problem 1519

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Re:不要想复杂，按照字符串输入之后，就for (i=0;s[i];i++) {n+=s[i]-'0'; if (n>9) n-=9;}就这就搞定了哈。 (19) babyaries 2007-11-21 11:47:30
Re:不要想复杂，按照字符串输入之后，就for (i=0;s[i];i++) {n+=s[i]-'0'; if (n>9) n-=9;}就这就搞定了哈。 (4) 031064212 2008-04-24 19:12:44
Re:不要想复杂，按照字符串输入之后，就for (i=0;s[i];i++) {n+=s[i]-'0'; if (n>9) n-=9;}就这就搞定了哈。 (28) 20083331 2009-04-29 09:34:49

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