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继续求数据!!!!!!!!!!!!

Posted by crackerwang at 2007-09-29 08:00:57 on Problem 3399
In Reply To:那这样做有什么问题呢??? Posted by:crackerwang at 2007-09-29 07:50:37
> 		sort(a,a+n);
> 		i=0;
> 		j=n-1;
> 		while(k)
> 		{
> 			if(k>=2)
> 			{
> 				t1=a[i]*a[i+1];
> 				t2=a[j]*a[j-1];
> 				if(t1>=t2)
> 				{
> 					flag[i]=flag[i+1]=1;
> 					i=i+2;
> 				}
> 				else
> 				{
> 					flag[j]=flag[j-1]=1;
> 					j-=2;
> 				}
> 				k-=2;
> 			}
> 			else
> 			{
> 				flag[j]=1;
> 				k=0;
> 			}
> 		}

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