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Re:没有枚举完全,应该这样do{...}while(next_permutation);In Reply To:请问这个枚举哪里错了 Posted by:shhu at 2007-08-26 10:28:21 > 这个个数据我得到的是38,答案是37
> 8
> 0 1 2 3 4 5 6 7 8
> 1 0 2 3 4 5 6 7 8
> 1 2 0 3 4 5 6 7 8
> 1 2 3 0 4 5 6 7 8
> 1 2 3 4 0 5 6 7 8
> 1 2 3 4 5 0 6 7 8
> 1 2 3 4 5 6 0 7 8
> 1 2 3 4 5 6 7 0 8
> 1 2 3 4 5 6 7 8 0
> #include<cstdio>
> #include<algorithm>
> using namespace std;
> int d[20][20],path[20],mint;
> int main()
> {
> int n,i,j,s,t;
> while(scanf("%d",&n)&&n)
> {
> for(i=0;i<=n;i++)
> for(j=0;j<=n;j++)
> scanf("%d",&d[i][j]);
> for(i=0;i<=n;i++)
> for(s=0;s<=n;s++)
> for(t=0;t<=n;t++)
> d[s][t]=min(d[s][t],d[s][i]+d[i][t]);
> for(i=0;i<=n;i++)
> path[i]=i;
> path[n+1]=0;
> mint=0x3fffffff;
> while(next_permutation(path+1,path+n+1))
> {
> s=0;
> for(i=0;i<=n;i++)
> s+=d[path[i]][path[i+1]];
> mint=min(mint,s);
>
> }
> printf("%d\n",mint);
> }
> return 0;
> }
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