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只要证明n-1|x+y当且仅当n-1|nx+yn-1|x+y <=> n-1|(n-1)x+(x+y) <=> n-1|nx+y 所以所有的基数n都可以扔掉，题目就等价于n-1是否可以整除各位数之和 Followed by: Post your reply here: |
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