The jth value on the ith line indicates the time to go directly from location i to location j without visiting any other locations along the way
好像弄倒了

    for(i=0;i<=n;i++)
            for(j=0;j<=n;j++)
                scanf("%d",&d[j][i]);
换成这样就ac了，真不知怎么搞的
> 这个个数据我得到的是38，答案是37
> 8
> 0 1 2 3 4 5 6 7 8
> 1 0 2 3 4 5 6 7 8
> 1 2 0 3 4 5 6 7 8
> 1 2 3 0 4 5 6 7 8
> 1 2 3 4 0 5 6 7 8
> 1 2 3 4 5 0 6 7 8
> 1 2 3 4 5 6 0 7 8
> 1 2 3 4 5 6 7 0 8
> 1 2 3 4 5 6 7 8 0
> #include<cstdio>
> #include<algorithm>
> using namespace std;
> int d[20][20],path[20],mint;
> int main()
> {
>     int n,i,j,s,t;
>     while(scanf("%d",&n)&&n)
>     {
>         for(i=0;i<=n;i++)
>             for(j=0;j<=n;j++)
>                 scanf("%d",&d[i][j]);
>         for(i=0;i<=n;i++)
>             for(s=0;s<=n;s++)
>                 for(t=0;t<=n;t++)
>                     d[s][t]=min(d[s][t],d[s][i]+d[i][t]);
>         for(i=0;i<=n;i++)
>             path[i]=i;
>         path[n+1]=0;
>         mint=0x3fffffff;
>         while(next_permutation(path+1,path+n+1))
>         {
>             s=0;
>             for(i=0;i<=n;i++)
>                 s+=d[path[i]][path[i+1]];
>             mint=min(mint,s);
>             
>         }
>         printf("%d\n",mint);
>     }
>     return 0;
> }