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Why wrong answer??有测试数据吗#include <cstdio> #include <algorithm> using namespace std; typedef struct { double x; double y; }Point; typedef struct { Point pt1; Point pt2; }Segment; Point pt; double left[100],right[100],top[100],bottom[100]; Point mid[1000]; Segment sgmt[31]; double multi(Point p1, Point p2, Point p0) { //求矢量[p0, p1], [p0, p2]的叉积 //p0是顶点 return (p1.x - p0.x) * (p2.y - p0.y) - (p2.x - p0.x) * (p1.y - p0.y); //若结果等于0,则这三点共线 //若结果大于0,则p0p2在p0p1的逆时针方向 //若结果小于0,则p0p2在p0p1的顺时针方向 } double max(double x, double y) { //比较两个数的大小,返回大的数 return x > y ? x : y; } double min(double x, double y) { //比较两个数的大小,返回小的数 return x < y ? x : y; } bool isIntersected(Point s1, Point e1, Point s2, Point e2) { //判断线段是否相交 //1.快速排斥试验判断以两条线段为对角线的两个矩形是否相交 //2.跨立试验 if( (max(s1.x, e1.x) >= min(s2.x, e2.x)) && (max(s2.x, e2.x) >= min(s1.x, e1.x)) && (max(s1.y, e1.y) >= min(s2.y, e2.y)) && (max(s2.y, e2.y) >= min(s1.y, e1.y)) && (multi(s2, e1, s1) * multi(e1, e2, s1) >= 0) && (multi(s1, e2, s2) * multi(e2, e1, s2) >= 0) ) return true; return false; } int main() { int n,i,j; int lf = 1,rt = 1,tp = 1,btm = 1; int counter = 0; int res,min = 99999999; left[0] = 0; right[0] = 0; top[0] = 0; bottom[0] = 0; scanf("%d",&n); for(i = 0; i < n; i ++) { scanf("%lf%lf",&pt.x,&pt.y); sgmt[i].pt1.x = pt.x; sgmt[i].pt1.y = pt.y; if(pt.x == 0) left[lf++] = pt.y; if(pt.x == 100) right[rt++] = pt.y; if(pt.y == 0) bottom[btm++] = pt.x; if(pt.y == 100) top[tp++] = pt.x; scanf("%lf%lf",&pt.x,&pt.y); sgmt[i].pt2.x = pt.x; sgmt[i].pt2.y = pt.y; if(pt.x == 0) left[lf++] = pt.y; if(pt.x == 100) right[rt++] = pt.y; if(pt.y == 0) bottom[btm++] = pt.x; if(pt.y == 100) top[tp++] = pt.x; } scanf("%lf%lf",&pt.x,&pt.y);//宝物的坐标 left[lf++] = 100; right[rt++] = 100; top[tp++] = 100; bottom[btm++] = 100; sort(left,left+lf); sort(right,right+rt); sort(top,top+tp); sort(bottom,bottom+btm); for(i = 0; i < lf-1; i++)//求中点 { mid[counter].x = 0; mid[counter].y = ( left[i] + left[i+1] ) / 2; counter++; } for(i = 0; i < rt-1; i++) { mid[counter].x = 100; mid[counter].y = ( right[i] + right[i+1] ) / 2; counter++; } for(i = 0; i < tp-1; i++) { mid[counter].y = 100; mid[counter].x = ( top[i] + top[i+1] ) / 2; counter++; } for(i = 0; i < btm-1; i++) { mid[counter].y = 0; mid[counter].y = ( bottom[i] + bottom[i+1] ) / 2; counter++; } for(i = 0; i < counter; i++) { printf("%lf %lf\n",mid[i].x,mid[i].y); res = 0; for(j = 0; j < n; j++) { if(isIntersected(sgmt[j].pt1,sgmt[j].pt2,pt,mid[i])) res++; } if(res < min) min = res; } printf("Number of doors = %d\n",min+1); return 0; } Followed by:
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