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请问大家，这个时候输出多少？4 2 2 1 3 2 有人的过了的程序输出3， 算法是用传递闭包加边 因为总的关系是n*(n-1)/2 因此只要算出已知的边 就可以知道未知需要的边数了 但是只要知道4大于3就可以了 ，所以只需要1次？ Followed by:
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