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是不是可以模拟拓扑排序？如果某个节点比另一个节点小，那么它的入度就加1 每次当只有一个入度为0时，把它取出。 如果有n个节点同时为0度，那么就添加 n*(n-1)/2条边 也即 多比较n*(n-1)/2次 是不是这样啊，请多多指教啊！哈哈！ Followed by:
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