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Re:是a(n+1)+n*a0....吧

Posted by 10305119 at 2007-07-16 21:20:56 on Problem 2601
In Reply To:Re:是a(n+1)+n*a0....吧 Posted by:10305119 at 2007-07-16 21:17:52 
> 公式好像不对吧？
> a(1) = ( n * a0-a(n+1)- 2 * ((c1 + c2 + ...+ cn) +  (c1 + c2 + ... + cn-1) + ... + (c1 + c2) + c1) / (n + 1)
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