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Re:是a(n+1)+n*a0....吧In Reply To:Re:是a(n+1)+n*a0....吧 Posted by:lxp_rs at 2006-08-25 00:12:58 公式好像不对吧？ a(1) = ( n * a0-a(n+1)- 2 * ((c1 + c2 + ...+ cn) + (c1 + c2 + ... + cn-1) + ... + (c1 + c2) + c1) / (n + 1) Followed by:
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