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Re:Help me.thanks.

Posted by fify at 2007-07-12 15:46:09 on Problem 3154
In Reply To:Help me.thanks. Posted by:kuangwenkui at 2007-06-16 16:30:42
> #include<stdio.h>
> main()
> {float a,sum[100],p,q,s=0;
> int i,j,k,n,m;
>   for(k=1;k<100 ;k++)
>      {printf("sample input #%d\n",k);
>        scanf("%d %d",&n,&m);
>        for(i=1;i<n;i++)
> 	  { sum[i]=1;
> 	  for(j=1;j<m+n;j++)
> 	      { p=(float)(i/n);
> 	       q=(float)(j/(m+n));printf("%f %f",p,q);
> 	      if( p>q)
> 		 a=p-q;
> 		 else a=q-p;
> 	      if(sum[i]>a)
> 		  sum[i]=a;
> 	       else continue;
> 	      }
> 	    s=sum[i]+s;
> 	   }
> 	   s=s*10000;
> 	 printf("sample output #%d\n%.4f\n",k,s);
> 	}
> }

No "sample input" or "sample output" needed in the printf function!

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