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Re:Help me.thanks.In Reply To:Help me.thanks. Posted by:kuangwenkui at 2007-06-16 16:30:42 > #include<stdio.h> > main() > {float a,sum[100],p,q,s=0; > int i,j,k,n,m; > for(k=1;k<100 ;k++) > {printf("sample input #%d\n",k); > scanf("%d %d",&n,&m); > for(i=1;i<n;i++) > { sum[i]=1; > for(j=1;j<m+n;j++) > { p=(float)(i/n); > q=(float)(j/(m+n));printf("%f %f",p,q); > if( p>q) > a=p-q; > else a=q-p; > if(sum[i]>a) > sum[i]=a; > else continue; > } > s=sum[i]+s; > } > s=s*10000; > printf("sample output #%d\n%.4f\n",k,s); > } > } No "sample input" or "sample output" needed in the printf function! Followed by: Post your reply here: |
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